The sudden chemistry of Electrolysis
The sudden chemistry of Electrolysis
We all know that a piece of metal conducts electricity well. And we also know we should not touch the metal if it conducts high amount of electricity. So how does this really happen? The basic types of bonds in chemistry are as two types as primary and secondary. The primary bonds are then categorized into 3 parts called Covalent, Ionic and Metallic bindings. Here, a metallic binding between the metal atoms in the piece have free river of electrons floating in. Now, the extra flow of electrons by the electric current can use these atoms as their medium to move (We’ve sent a separate article for the bindings, see it first). What’s really happening is this flow of electrons.
Actually how do they make these rivers of electrons? This is
how it happens; an atom should always be in a neutral charge to equally share
their number of electrons which are negatively charged and the number of
protons which are positive. For a metallic atom like for an example aluminum
removes its electrons in the ground state and makes a full river of it. While a
removed electron is negative, the charge of the atom or now it is an ion is
positive. So they tend to conduct electricity.
The direct opposite happens to poor Chlorine. It generally has +17 in the nucleus and -17 charge in the electrons. So its 0. But as it takes one electron, it becomes -18. So 17-18=-1. So we call it a negative ion or an anion.
So the Sodium cation is +1 charged and Chlorine anion is -1 charged. but when the compound forms, they get together and 1-1=0 and become chargeless. And notice that sodium which is a metal has taken the positive charge while chlorine, the non- metal has taken the negative one. So in theory, metals are mostly cations and non-metals are anions.
These salts stay in very hard crystalline forms as above, but they easily dissolve in water. The best example is salt. When they dissolve, their normal NaCl type breaks and separate into ions. So when they are aqueous, their normal form is Na+ and Cl-. We know that water is made from hydrogen and oxygen, H2O. Which means there are 2 hydrogens and one oxygen. When the salt is dissolved in water, water too divide into pieces, H+ and OH-. OH- in case is made from 2 elements. But it is negatively charged as the H+ cation is positive.Now think there is a salt solution as below. 2 terminals, + and - are connected from a battery pack (almost 12V). We have used carbon rods as the terminals because in the mean process, some reactions could occur and if we use metals such as a piece of iron, it will react and add neighbour substances.
The Sodium and the Hydrogen ions are + charged, so they should take an electron to be normal so they go and take one from the negative terminal. And the Hydroxide (OH) ions and chlorine ions which are negatively charged move to positive terminal to get rid of the electron. As 2 of the chlorine ions remove a electrons, it transmit to Cl2 gas (Shown in yellow). And so on oppositely, 2 of the hydrogens get used buy some electrons and free up being H2 gas.
2(H+) + 2(e-) = H2
2(Cl-) = Cl2 + 2(e-)
So each product of chlorine and hydrogen come out of each + and - electrode respectively. But there is something remaining. The remaining OH ion can not turn into a gas of H2O2 (Hydrogen peroxide) as well as the Na. Sodium is generally a metal, and not a gas and because of its extremely high reactivity, the emerging Na reacts directly with OH and make NaOH Sodium hydroxide. We can once test the product of it as because NaOH is a strong base, it can turn an indicator to a base colour. Sure we can make this wonderful compound at home with a battery and some salt, but the problem is in case, the Cl2 gas emitted will not be 100% and some of the Cl2 gas can re dissolve in the water and make it acidic a little. So when chlorine reacts with water, it forms HCl (Hydrochloric acid) and HClO (Hypochlorous acid) and it will react with NaOH to remake NaCl and a bit of bleach (NaClO). We can test it using an indicator.
The acid base indicator Blue pea ('Katarolu') doesn't indicate any colour with a NaCl solution because it is neutral.
But when the current is passing through the solution, the negative side of it turns green indicating it is basic and the positive terminal side turns colourless and pink a little. This is happening because Cl2 dissolves in water making it acidic. But with this indicator, an acid should be brightly pink, but in case HClO Hypochlorous acid is strong enough to crunch the colour of it. The slight pink is due to HCl.
But the yield of acid is not as 100% as NaOH. Because some Cl2 escape, the solution is considerably basic. Now what happens is that at the - terminal, H2 releases keeping OH alone so it binds with Na to form Sodium hydroxide. Even though there are some Cl- ions in the green basic region, it turns into the new colour because of the presence of the OH. That means, it's not the sodium that is showing the basic feature but the OH- group. But for many specialities of sodium, the compound turns out to be exaggeratedly basic. Both of the parts are separated from a regiform sheet which allows the two liquids to not pass each other reacting. But if we mix them each other, they will still show a light green colour because of the more NaOH yield.
What do you think if we electrolyse the NaOH solution more on? The NaOH re ionize to Na+ and OH-. As well as water to H+ and OH-. Then we are going to have 2 OH- groups. 2H+ just go off the negative terminal remaining the others. 2OH- becomes H2O2- as Hydrogen peroxide. One of its Oxygen, O- removes off to positive side leaving H2O. Now we have O2 gas in the positive side instead chlorine. H2O and Na reacts to form NaOH and H again. We then get another H atom at the - terminal. So 2 H2 goes of from negative and one O2 goes from positive terminal retaining NaOH. So it means that breaks water into H2O. But the basic property doesn't change.
Sometimes if we electrolyze a salt like CuSO4 Copper sulfate, we get pure Cu copper metal out from one electrode.
Hydrogen takes copper's place.
H2 + CuSO4 = Cu + H2SO4
Blue colour of the copper sulfate solution will decrease as it is electrolysed. The gas bubbles are oxygen and hydrogen.
The main use of electrolysis is electroplating which is painting a metal on another metal type. This is done by connecting the metal which is to be plated in the negative terminal and the plated ingridient on the positive side. For this these should be a salt of the ingridient metal and also the metal should be less reactive than Hydrogen to stop reacting with acid and water. For an example, if you are plating iron with copper, you have to connect iron on the - terminal and a copper plate in the + terminal in a CuSO4 or CuCl copper chloride solution. If you are using Gold for the ingredient, you have to use a plate of gold in + side and a gold containing salt such as, AuSO4 gold sulfate. (Au is represented as Gold)